260=20(x^2)

Solution for 260=20(x^2) equation:

260=20(x^2)

We move all terms to the left:

260-(20(x^2))=0

determiningTheFunctionDomain
-20x^2+260=0

a = -20; b = 0; c = +260;
Δ = b2-4ac
Δ = 02-4·(-20)·260
Δ = 20800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20800}=\sqrt{1600*13}=\sqrt{1600}*\sqrt{13}=40\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{13}}{2*-20}=\frac{0-40\sqrt{13}}{-40}
=-\frac{40\sqrt{13}}{-40}
=-\frac{\sqrt{13}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{13}}{2*-20}=\frac{0+40\sqrt{13}}{-40}
=\frac{40\sqrt{13}}{-40}
=\frac{\sqrt{13}}{-1}
$